(4x-16)/(x^2-8x+16)

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Solution for (4x-16)/(x^2-8x+16) equation: 


D( x )

x^2-(8*x)+16 = 0

x^2-(8*x)+16 = 0

x^2-(8*x)+16 = 0

x^2-8*x+16 = 0

x^2-8*x+16 = 0

DELTA = (-8)^2-(1*4*16)

DELTA = 0

x = 8/(1*2)

x = 4 or x = 4

x in (-oo:4) U (4:+oo)

(4*x-16)/(x^2-(8*x)+16) = 0

(4*x-16)/(x^2-8*x+16) = 0

x^2-8*x+16 = 0

x^2-8*x+16 = 0

DELTA = (-8)^2-(1*4*16)

DELTA = 0

x = 8/(1*2)

x = 4 or x = 4

(x-4)^2 = 0

(4*x-16)/((x-4)^2) = 0

4*x-16 = 0 // + 16

4*x = 16 // : 4

x = 16/4

x = 4

x in { 4} 

x belongs to the empty set

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